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0.8d^2+2.4d=115
We move all terms to the left:
0.8d^2+2.4d-(115)=0
a = 0.8; b = 2.4; c = -115;
Δ = b2-4ac
Δ = 2.42-4·0.8·(-115)
Δ = 373.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{373.76}}{2*0.8}=\frac{-2.4-\sqrt{373.76}}{1.6} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{373.76}}{2*0.8}=\frac{-2.4+\sqrt{373.76}}{1.6} $
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